5-7(a-4)=3(-4a+6)

Solution for 5-7(a-4)=3(-4a+6) equation:

5-7(a-4)=3(-4a+6)

We move all terms to the left:

5-7(a-4)-(3(-4a+6))=0

We multiply parentheses

-7a-(3(-4a+6))+28+5=0


We calculate terms in parentheses: -(3(-4a+6)), so:

3(-4a+6)

We multiply parentheses

-12a+18

Back to the equation:

-(-12a+18)


We add all the numbers together, and all the variables

-7a-(-12a+18)+33=0

We get rid of parentheses

-7a+12a-18+33=0

We add all the numbers together, and all the variables

5a+15=0

We move all terms containing a to the left, all other terms to the right

5a=-15

a=-15/5

a=-3