5-i/2i

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Solution for 5-i/2i equation: 


i in (-oo:+oo)

5-((i/2)*i) = 0

(-1/2)*i^2+5 = 0

-1/2*i^2 = -5 // : -1/2

i^2 = 10

i^2 = 10 // ^ 1/2

abs(i) = 10^(1/2)

i = 10^(1/2) or i = -10^(1/2)

i in { 10^(1/2), -10^(1/2) }

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