5-r/r2=2r-35

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Solution for 5-r/r2=2r-35 equation:


D( r )

r^2 = 0

r^2 = 0

r^2 = 0

1*r^2 = 0 // : 1

r^2 = 0

r = 0

r in (-oo:0) U (0:+oo)

5-(r/(r^2)) = 2*r-35 // - 2*r-35

5-(2*r)-(r/(r^2))+35 = 0

5-2*r-r^-1+35 = 0

40*r^0-2*r^1-1*r^-1 = 0

(40*r^1-2*r^2-1*r^0)/(r^1) = 0 // * r^2

r^1*(40*r^1-2*r^2-1*r^0) = 0

r^1

40*r-2*r^2-1 = 0

40*r-2*r^2-1 = 0

DELTA = 40^2-(-2*(-1)*4)

DELTA = 1592

DELTA > 0

r = (1592^(1/2)-40)/(-2*2) or r = (-1592^(1/2)-40)/(-2*2)

r = (2*398^(1/2)-40)/(-4) or r = (-2*398^(1/2)-40)/(-4)

r in { (2*398^(1/2)-40)/(-4), (-2*398^(1/2)-40)/(-4)}

r in { (2*398^(1/2)-40)/(-4), (-2*398^(1/2)-40)/(-4) }

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