5-x=(1/2)x+4

Solution for 5-x=(1/2)x+4 equation:

5-x=(1/2)x+4

We move all terms to the left:

5-x-((1/2)x+4)=0


Domain of the equation: 2)x+4)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-x-((+1/2)x+4)+5=0

We add all the numbers together, and all the variables

-1x-((+1/2)x+4)+5=0

We multiply all the terms by the denominator


-1x*2)x+4)-((+5*2)x+4)+1=0

We add all the numbers together, and all the variables

-1x*2)x+4)-(10x+4)+1=0

Wy multiply elements

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$