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5-x=1/2x+
We move all terms to the left:
5-x-(1/2x+)=0
Domain of the equation: 2x+)!=0We add all the numbers together, and all the variables
x∈R
-x-(+1/2x)+5=0
We add all the numbers together, and all the variables
-1x-(+1/2x)+5=0
We get rid of parentheses
-1x-1/2x+5=0
We multiply all the terms by the denominator
-1x*2x+5*2x-1=0
Wy multiply elements
-2x^2+10x-1=0
a = -2; b = 10; c = -1;
Δ = b2-4ac
Δ = 102-4·(-2)·(-1)
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{23}}{2*-2}=\frac{-10-2\sqrt{23}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{23}}{2*-2}=\frac{-10+2\sqrt{23}}{-4} $
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