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5-x=1/2x+3
We move all terms to the left:
5-x-(1/2x+3)=0
Domain of the equation: 2x+3)!=0We add all the numbers together, and all the variables
x∈R
-1x-(1/2x+3)+5=0
We get rid of parentheses
-1x-1/2x-3+5=0
We multiply all the terms by the denominator
-1x*2x-3*2x+5*2x-1=0
Wy multiply elements
-2x^2-6x+10x-1=0
We add all the numbers together, and all the variables
-2x^2+4x-1=0
a = -2; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·(-2)·(-1)
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{2}}{2*-2}=\frac{-4-2\sqrt{2}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{2}}{2*-2}=\frac{-4+2\sqrt{2}}{-4} $
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