5/(10+4x)*20+8x

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Solution for 5/(10+4x)*20+8x equation: 


D( x )

4*x+10 = 0

4*x+10 = 0

4*x+10 = 0

4*x+10 = 0 // - 10

4*x = -10 // : 4

x = -10/4

x = -5/2

x in (-oo:-5/2) U (-5/2:+oo)

20*(5/(4*x+10))+8*x = 0

(5*20)/(4*x+10)+8*x = 0

(5*20)/(4*x+10)+(8*x*(4*x+10))/(4*x+10) = 0

8*x*(4*x+10)+5*20 = 0

32*x^2+80*x+100 = 0

32*x^2+80*x+100 = 0

4*(8*x^2+20*x+25) = 0

8*x^2+20*x+25 = 0

DELTA = 20^2-(4*8*25)

DELTA = -400

DELTA < 0

4 = 0

4/(4*x+10) = 0

4/(4*x+10) = 0 // * 4*x+10

4 = 0

x belongs to the empty set

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