5/(2-z)=3z

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Solution for 5/(2-z)=3z equation: 


D( z )

2-z = 0

2-z = 0

2-z = 0

2-z = 0 // - 2

-z = -2 // * -1

z = 2

z in (-oo:2) U (2:+oo)

5/(2-z) = 3*z // - 3*z

5/(2-z)-(3*z) = 0

5/(2-z)-3*z = 0

5/(2-z)+(-3*z*(2-z))/(2-z) = 0

5-3*z*(2-z) = 0

3*z^2-6*z+5 = 0

3*z^2-6*z+5 = 0

3*z^2-6*z+5 = 0

DELTA = (-6)^2-(3*4*5)

DELTA = -24

DELTA < 0

1 = 0

1/(2-z) = 0

1/(2-z) = 0 // * 2-z

1 = 0

z belongs to the empty set

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