5/(2x)+3=7/x

Solution for 5/(2x)+3=7/x equation:

5/(2x)+3=7/x

We move all terms to the left:

5/(2x)+3-(7/x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

5/2x-(+7/x)+3=0

We get rid of parentheses

5/2x-7/x+3=0

We calculate fractions


5x/2x^2+(-14x)/2x^2+3=0

We multiply all the terms by the denominator


5x+(-14x)+3*2x^2=0

Wy multiply elements

6x^2+5x+(-14x)=0

We get rid of parentheses

6x^2+5x-14x=0

We add all the numbers together, and all the variables

6x^2-9x=0

a = 6; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·6·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*6}=\frac{18}{12}
=1+1/2
$