5/(2x+6)=1/(4x)

Solution for 5/(2x+6)=1/(4x) equation:

5/(2x+6)=1/(4x)

We move all terms to the left:

5/(2x+6)-(1/(4x))=0


Domain of the equation: (2x+6)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-6

x!=-6/2

x!=-3

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

5/(2x+6)-(+1/4x)=0

We get rid of parentheses

5/(2x+6)-1/4x=0

We calculate fractions


20x/(8x^2+24x)+(-1*(2x+6))/(8x^2+24x)=0


We calculate terms in parentheses: +(-1*(2x+6))/(8x^2+24x), so:

-1*(2x+6))/(8x^2+24x

We add all the numbers together, and all the variables

24x-1*(2x+6))/(8x^2

We multiply all the terms by the denominator


24x*(8x^2-1*(2x+6))

Back to the equation:

+(24x*(8x^2-1*(2x+6)))


We multiply all the terms by the denominator


20x+((24x*(8x^2-1*(2x+6))))*(8x^2+24x)=0


We calculate terms in parentheses: +((24x*(8x^2-1*(2x+6))))*(8x^2+24x), so:

(24x*(8x^2-1*(2x+6))))*(8x^2+24x

We add all the numbers together, and all the variables

24x+(24x*(8x^2-1*(2x+6))))*(8x^2

Back to the equation:

+(24x+(24x*(8x^2-1*(2x+6))))*(8x^2)