5/(2x+6)=1/21x

Solution for 5/(2x+6)=1/21x equation:

5/(2x+6)=1/21x

We move all terms to the left:

5/(2x+6)-(1/21x)=0


Domain of the equation: (2x+6)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-6

x!=-6/2

x!=-3

x∈R



Domain of the equation: 21x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

5/(2x+6)-(+1/21x)=0

We get rid of parentheses

5/(2x+6)-1/21x=0

We calculate fractions


105x/(42x^2+126x)+(-1*(2x+6))/(42x^2+126x)=0


We calculate terms in parentheses: +(-1*(2x+6))/(42x^2+126x), so:

-1*(2x+6))/(42x^2+126x

We add all the numbers together, and all the variables

126x-1*(2x+6))/(42x^2

We multiply all the terms by the denominator


126x*(42x^2-1*(2x+6))

Back to the equation:

+(126x*(42x^2-1*(2x+6)))


We multiply all the terms by the denominator


105x+((126x*(42x^2-1*(2x+6))))*(42x^2+126x)=0


We calculate terms in parentheses: +((126x*(42x^2-1*(2x+6))))*(42x^2+126x), so:

(126x*(42x^2-1*(2x+6))))*(42x^2+126x

We add all the numbers together, and all the variables

126x+(126x*(42x^2-1*(2x+6))))*(42x^2

Back to the equation:

+(126x+(126x*(42x^2-1*(2x+6))))*(42x^2)