5/(2x-1)0

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Solution for 5/(2x-1)0 equation: 


D( x )

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

5/(2*x-1) > 0

( 2*x-1 )

2*x-1 > 0 // + 1

2*x > 1 // : 2

x > 1/2

( 5 )

5 > 0

x należy do R

	(-oo:1/2)	(1/2:+oo)
2*x-1	-	+
5	+	+


x in (1/2:+oo)

(1/2:+oo)

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