5/(4x+6)=10/(3-2x)

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Solution for 5/(4x+6)=10/(3-2x) equation:


D( x )

3-(2*x) = 0

4*x+6 = 0

3-(2*x) = 0

3-(2*x) = 0

3-2*x = 0

3-2*x = 0 // - 3

-2*x = -3 // : -2

x = -3/(-2)

x = 3/2

4*x+6 = 0

4*x+6 = 0

4*x+6 = 0 // - 6

4*x = -6 // : 4

x = -6/4

x = -3/2

x in (-oo:-3/2) U (-3/2:3/2) U (3/2:+oo)

5/(4*x+6) = 10/(3-(2*x)) // - 10/(3-(2*x))

5/(4*x+6)-(10/(3-(2*x))) = 0

5/(4*x+6)-10*(3-2*x)^-1 = 0

5/(4*x+6)-10/(3-2*x) = 0

(5*(3-2*x))/((4*x+6)*(3-2*x))+(-10*(4*x+6))/((4*x+6)*(3-2*x)) = 0

5*(3-2*x)-10*(4*x+6) = 0

-50*x-45 = 0

(-50*x-45)/((4*x+6)*(3-2*x)) = 0

(-50*x-45)/((4*x+6)*(3-2*x)) = 0 // * (4*x+6)*(3-2*x)

-50*x-45 = 0

-50*x-45 = 0 // + 45

-50*x = 45 // : -50

x = 45/(-50)

x = -9/10

x = -9/10

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