5/(t-3)=10

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Solution for 5/(t-3)=10 equation: 


D( t )

t-3 = 0

t-3 = 0

t-3 = 0

t-3 = 0 // + 3

t = 3

t in (-oo:3) U (3:+oo)

5/(t-3) = 10 // - 10

5/(t-3)-10 = 0

5/(t-3)+(-10*(t-3))/(t-3) = 0

5-10*(t-3) = 0

35-10*t = 0

(35-10*t)/(t-3) = 0

(35-10*t)/(t-3) = 0 // * t-3

35-10*t = 0

35-10*t = 0 // - 35

-10*t = -35 // : -10

t = -35/(-10)

t = 7/2

t = 7/2

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