If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x+1 = 0
x-8 = 0
x = 0
x = 0
x+1 = 0
x+1 = 0
x+1 = 0 // - 1
x = -1
x-8 = 0
x-8 = 0
x-8 = 0 // + 8
x = 8
x in (-oo:-1) U (-1:0) U (0:8) U (8:+oo)
5/(x+1) = 2/(x-8)+1/x // - 2/(x-8)+1/x
5/(x+1)-(2/(x-8))-(1/x) = 0
5/(x+1)-2*(x-8)^-1-x^-1 = 0
5/(x+1)-2/(x-8)-1/x = 0
(5*x*(x-8))/(x*(x+1)*(x-8))+(-2*x*(x+1))/(x*(x+1)*(x-8))+(-1*(x+1)*(x-8))/(x*(x+1)*(x-8)) = 0
5*x*(x-8)-2*x*(x+1)-1*(x+1)*(x-8) = 0
3*x^2-x^2-42*x+7*x+8 = 0
2*x^2-35*x+8 = 0
2*x^2-35*x+8 = 0
2*x^2-35*x+8 = 0
DELTA = (-35)^2-(2*4*8)
DELTA = 1161
DELTA > 0
x = (1161^(1/2)+35)/(2*2) or x = (35-1161^(1/2))/(2*2)
x = (3*129^(1/2)+35)/4 or x = (35-3*129^(1/2))/4
(x-((35-3*129^(1/2))/4))*(x-((3*129^(1/2)+35)/4)) = 0
((x-((35-3*129^(1/2))/4))*(x-((3*129^(1/2)+35)/4)))/(x*(x+1)*(x-8)) = 0
((x-((35-3*129^(1/2))/4))*(x-((3*129^(1/2)+35)/4)))/(x*(x+1)*(x-8)) = 0 // * x*(x+1)*(x-8)
(x-((35-3*129^(1/2))/4))*(x-((3*129^(1/2)+35)/4)) = 0
( x-((3*129^(1/2)+35)/4) )
x-((3*129^(1/2)+35)/4) = 0 // + (3*129^(1/2)+35)/4
x = (3*129^(1/2)+35)/4
( x-((35-3*129^(1/2))/4) )
x-((35-3*129^(1/2))/4) = 0 // + (35-3*129^(1/2))/4
x = (35-3*129^(1/2))/4
x in { (3*129^(1/2)+35)/4, (35-3*129^(1/2))/4 }
| 4/5x5/2 | | X^2+8x+10=10 | | 5(2p-5)+2(p-3)=4(p-1) | | 50-x^2=14 | | 7x^2+42x+70=0 | | 6x^2+9x+-8-12= | | ln(x)+ln(4-x)=ln(3) | | 2xy-2x-y=0 | | 81x^2+162x+75=0 | | x=3x+40 | | x^2+26= | | 6*17+17*6/7 | | (12.5-8)/2.8 | | 12.5-8/2.8 | | x^3-6x^2+16x=0 | | 5x*2x=90m^3 | | x^2-10x=6 | | 17x=384m^3 | | 5x+10=8x-20 | | 6ln(6x)=12 | | 4x*x*12x=384m^3 | | 9x+3+3x-4= | | 2x*5x=90 | | 6x+40=14-41 | | 2x^2+27x-6.7=0 | | X-5/8=31/4 | | (3/2)x+80=2x | | 0.5-(-15/30)= | | 0.5*(-3+4)= | | y+5x+6+4+2y= | | 12x+7=167-8x | | 16x^2-(1/25)=0 |