5/(x+1)=7/2x

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Solution for 5/(x+1)=7/2x equation: 



5/(x+1)=7/2x

We move all terms to the left:

5/(x+1)-(7/2x)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

5/(x+1)-(+7/2x)=0

We get rid of parentheses

5/(x+1)-7/2x=0

We calculate fractions


10x/(2x^2+2x)+(-7x-7)/(2x^2+2x)=0

We multiply all the terms by the denominator


10x+(-7x-7)=0

We get rid of parentheses

10x-7x-7=0

We add all the numbers together, and all the variables

3x-7=0

We move all terms containing x to the left, all other terms to the right

3x=7

x=7/3

x=2+1/3

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