5/(x+2)=2/(x-1)

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Solution for 5/(x+2)=2/(x-1) equation: 



5/(x+2)=2/(x-1)

We move all terms to the left:

5/(x+2)-(2/(x-1))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x-1))!=0

x∈R



We calculate fractions


5x/((x+2)*(x-1)))+(-(2*(x+2))/((x+2)*(x-1)))=0



We calculate terms in parentheses: -(2*(x+2))/((x+2)*(x-1))), so:

2*(x+2))/((x+2)*(x-1))

We multiply all the terms by the denominator


2*(x+2))

We multiply parentheses

2x+

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

-2x+5x/((x+2)*(x-1)))+(=0

We multiply all the terms by the denominator


-2x*((x+2)*(x-1)))+(+5x=0

We add all the numbers together, and all the variables

5x-2x*((x+2)*(x-1)))+(=0

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