5/(x+4)+2=7/(x-3)

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Solution for 5/(x+4)+2=7/(x-3) equation: 



5/(x+4)+2=7/(x-3)

We move all terms to the left:

5/(x+4)+2-(7/(x-3))=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: (x-3))!=0

x∈R



We calculate fractions


5x/((x+4)*(x-3)))+(-(7*(x+4))/((x+4)*(x-3)))+2=0

We calculate fractions


(5x*((x+4)*(x-3)))+2)/(((x+4)*(x-3)))+(*((x+4)*(x-3)))+2)+(-(7*(x+4))*((x+4)*(x-3)))+()/(((x+4)*(x-3)))+(*((x+4)*(x-3)))+2)=0



We calculate terms in parentheses: +(5x*((x+4)*(x-3))), so:

5x*((x+4)*(x-3))



We can not solve this equation

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