5/(x-3)-6=12/(x-3)

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Solution for 5/(x-3)-6=12/(x-3) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

5/(x-3)-6 = 12/(x-3) // - 12/(x-3)

5/(x-3)-(12/(x-3))-6 = 0

5/(x-3)-12*(x-3)^-1-6 = 0

5/(x-3)-12/(x-3)-6 = 0

5/(x-3)-12/(x-3)+(-6*(x-3))/(x-3) = 0

5-6*(x-3)-12 = 0

18-6*x-7 = 0

11-6*x = 0

(11-6*x)/(x-3) = 0

(11-6*x)/(x-3) = 0 // * x-3

11-6*x = 0

11-6*x = 0 // - 11

-6*x = -11 // : -6

x = -11/(-6)

x = 11/6

x = 11/6

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