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5/(x-4)-4=3/(x-2)
We move all terms to the left:
5/(x-4)-4-(3/(x-2))=0
Domain of the equation: (x-4)!=0
We move all terms containing x to the left, all other terms to the right
x!=4
x∈R
Domain of the equation: (x-2))!=0We calculate fractions
x∈R
5x/((x-4)*(x-2)))+(-(3*(x-4))/((x-4)*(x-2)))-4=0
We calculate fractions
(5x*((x-4)*(x-2)))-4)/(((x-4)*(x-2)))+(*((x-4)*(x-2)))-4)+(-(3*(x-4))*((x-4)*(x-2)))+()/(((x-4)*(x-2)))+(*((x-4)*(x-2)))-4)=0
We calculate terms in parentheses: +(5x*((x-4)*(x-2))), so:We can not solve this equation
5x*((x-4)*(x-2))
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