5/(y-7)=3/(y-5)

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Solution for 5/(y-7)=3/(y-5) equation: 



5/(y-7)=3/(y-5)

We move all terms to the left:

5/(y-7)-(3/(y-5))=0



Domain of the equation: (y-7)!=0

We move all terms containing y to the left, all other terms to the right

y!=7

y∈R





Domain of the equation: (y-5))!=0

y∈R



We calculate fractions


5y/((y-7)*(y-5)))+(-(3*(y-7))/((y-7)*(y-5)))=0



We calculate terms in parentheses: -(3*(y-7))/((y-7)*(y-5))), so:

3*(y-7))/((y-7)*(y-5))

We multiply all the terms by the denominator


3*(y-7))

We multiply parentheses

3y+

We add all the numbers together, and all the variables

3y

Back to the equation:

-(3y)



We add all the numbers together, and all the variables

-3y+5y/((y-7)*(y-5)))+(=0

We multiply all the terms by the denominator


-3y*((y-7)*(y-5)))+(+5y=0

We add all the numbers together, and all the variables

5y-3y*((y-7)*(y-5)))+(=0

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