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5/12-4=3/4+2x
We move all terms to the left:
5/12-4-(3/4+2x)=0
Domain of the equation: 4+2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x)!=-4
x!=-4/1
x!=-4
x∈R
-(+2x+3/4)-4+5/12=0
We get rid of parentheses
-2x-4-3/4+5/12=0
We calculate fractions
There is no solution for this equation
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