5/12v+22=32

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Solution for 5/12v+22=32 equation: 



5/12v+22=32

We move all terms to the left:

5/12v+22-(32)=0



Domain of the equation: 12v!=0

v!=0/12

v!=0

v∈R



We add all the numbers together, and all the variables

5/12v-10=0

We multiply all the terms by the denominator


-10*12v+5=0

Wy multiply elements

-120v+5=0

We move all terms containing v to the left, all other terms to the right

-120v=-5

v=-5/-120

v=1/24

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