5/2(2x+1)=2/5(x-3)

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Solution for 5/2(2x+1)=2/5(x-3) equation: 



5/2(2x+1)=2/5(x-3)

We move all terms to the left:

5/2(2x+1)-(2/5(x-3))=0



Domain of the equation: 2(2x+1)!=0

x∈R





Domain of the equation: 5(x-3))!=0

x∈R



We calculate fractions


(25xx/(2(2x+1)*5(x-3)))+(-4x2/(2(2x+1)*5(x-3)))=0



We calculate terms in parentheses: +(25xx/(2(2x+1)*5(x-3))), so:

25xx/(2(2x+1)*5(x-3))

We multiply all the terms by the denominator


25xx

Back to the equation:

+(25xx)





We calculate terms in parentheses: +(-4x2/(2(2x+1)*5(x-3))), so:

-4x2/(2(2x+1)*5(x-3))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)



We get rid of parentheses

-4x^2+25xx=0

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