5/2(3x+4)=-1/3(-2x+7)

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Solution for 5/2(3x+4)=-1/3(-2x+7) equation:



5/2(3x+4)=-1/3(-2x+7)
We move all terms to the left:
5/2(3x+4)-(-1/3(-2x+7))=0
Domain of the equation: 2(3x+4)!=0
x∈R
Domain of the equation: 3(-2x+7))!=0
x∈R
We calculate fractions
(15x(-)/(2(3x+4)*3(-2x+7)))+(-(-2x3)/(2(3x+4)*3(-2x+7)))=0
We calculate terms in parentheses: +(15x(-)/(2(3x+4)*3(-2x+7))), so:
15x(-)/(2(3x+4)*3(-2x+7))
We add all the numbers together, and all the variables
15x0/(2(3x+4)*3(-2x+7))
We multiply all the terms by the denominator
15x0
We add all the numbers together, and all the variables
15x
Back to the equation:
+(15x)
We calculate terms in parentheses: +(-(-2x3)/(2(3x+4)*3(-2x+7))), so:
-(-2x3)/(2(3x+4)*3(-2x+7))
We add all the numbers together, and all the variables
-(-2x^3)/(2(3x+4)*3(-2x+7))
We multiply all the terms by the denominator
-(-2x^3)
We do not support expression: x^3

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