5/2(h+3)=19+6/7h

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Solution for 5/2(h+3)=19+6/7h equation: 



5/2(h+3)=19+6/7h

We move all terms to the left:

5/2(h+3)-(19+6/7h)=0



Domain of the equation: 2(h+3)!=0

h∈R





Domain of the equation: 7h)!=0

h!=0/1

h!=0

h∈R



We add all the numbers together, and all the variables

5/2(h+3)-(6/7h+19)=0

We get rid of parentheses

5/2(h+3)-6/7h-19=0

We calculate fractions


35h/(14h^2+42h)+(-12hh/(14h^2+42h)-19=0

We calculate fractions

We do not support ehpression: h^3

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