5/2(k-7)=4/5(7-k)

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Solution for 5/2(k-7)=4/5(7-k) equation: 



5/2(k-7)=4/5(7-k)

We move all terms to the left:

5/2(k-7)-(4/5(7-k))=0



Domain of the equation: 2(k-7)!=0

k∈R





Domain of the equation: 5(7-k))!=0

k∈R



We add all the numbers together, and all the variables

5/2(k-7)-(4/5(-1k+7))=0

We calculate fractions


(25k(-)/(2(k-7)*5(-1k+7)))+(-8kk/(2(k-7)*5(-1k+7)))=0



We calculate terms in parentheses: +(25k(-)/(2(k-7)*5(-1k+7))), so:

25k(-)/(2(k-7)*5(-1k+7))

We add all the numbers together, and all the variables

25k0/(2(k-7)*5(-1k+7))

We multiply all the terms by the denominator


25k0

We add all the numbers together, and all the variables

25k

Back to the equation:

+(25k)





We calculate terms in parentheses: +(-8kk/(2(k-7)*5(-1k+7))), so:

-8kk/(2(k-7)*5(-1k+7))

We multiply all the terms by the denominator


-8kk

Back to the equation:

+(-8kk)



We get rid of parentheses

25k-8kk=0

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