5/2(q-3)=2/5(q-1)

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Solution for 5/2(q-3)=2/5(q-1) equation: 



5/2(q-3)=2/5(q-1)

We move all terms to the left:

5/2(q-3)-(2/5(q-1))=0



Domain of the equation: 2(q-3)!=0

q∈R





Domain of the equation: 5(q-1))!=0

q∈R



We calculate fractions


(25qq/(2(q-3)*5(q-1)))+(-4qq/(2(q-3)*5(q-1)))=0



We calculate terms in parentheses: +(25qq/(2(q-3)*5(q-1))), so:

25qq/(2(q-3)*5(q-1))

We multiply all the terms by the denominator


25qq

Back to the equation:

+(25qq)





We calculate terms in parentheses: +(-4qq/(2(q-3)*5(q-1))), so:

-4qq/(2(q-3)*5(q-1))

We multiply all the terms by the denominator


-4qq

Back to the equation:

+(-4qq)



We get rid of parentheses

25qq-4qq=0

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