5/2=(3x-6)/1

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Solution for 5/2=(3x-6)/1 equation: 



5/2=(3x-6)/1

We move all terms to the left:

5/2-((3x-6)/1)=0

We calculate fractions


(-((3x-6)*2)/()+()/()=0



We calculate terms in parentheses: +(-((3x-6)*2)/()+()/(), so:

-((3x-6)*2)/()+()/(

We add all the numbers together, and all the variables

-((3x-6)*2)/()+1

We multiply all the terms by the denominator


-((3x-6)*2)+1*()



We calculate terms in parentheses: -((3x-6)*2), so:

(3x-6)*2

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-(6x-12)

We get rid of parentheses

-6x+12

Back to the equation:

+(-6x+12)



We get rid of parentheses

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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