5/2b=35

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Solution for 5/2b=35 equation: 



5/2b=35

We move all terms to the left:

5/2b-(35)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We multiply all the terms by the denominator


-35*2b+5=0

Wy multiply elements

-70b+5=0

We move all terms containing b to the left, all other terms to the right

-70b=-5

b=-5/-70

b=1/14

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