If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5/2c=19/3
We move all terms to the left:
5/2c-(19/3)=0
Domain of the equation: 2c!=0We add all the numbers together, and all the variables
c!=0/2
c!=0
c∈R
5/2c-(+19/3)=0
We get rid of parentheses
5/2c-19/3=0
We calculate fractions
There is no solution for this equation
| T(n+1)=4T(n)+1 | | 3(x+9)=-39 | | -8+5c=6+7c | | q-41-6=-8 | | 13+n/2=10 | | 10x=12-2 | | 12-7(7-2t)=2(t-1) | | 13+2r=-65 | | 1x-2=2-1x | | m/3-6=2 | | 12+x^2=4x+x^2 | | 0.05x+x=273 | | -11+x/3=-14 | | (5x^2)-5x=0 | | -2x-3=(-19) | | (7x+29)+(11x-31)=180 | | -7(-2+2x)=-154 | | x+2/2=x+4 | | (7x+29)+(12x-55)=180 | | 1+8(7-x)=10x=3 | | 5n=365 | | -18+v/13=-15 | | 420=40x | | 11x=2x+45 | | 11n-10n=11 | | |3x-6|9=0 | | 19+b/22=20 | | x^2-35x-120=0 | | 18c-14c=12 | | -4(8+5x)=-272 | | 2a-4a=10 | | 5x-3=9-x. |