5/2t-t=+3/2t

Solution for 5/2t-t=+3/2t equation:

5/2t-t=+3/2t

We move all terms to the left:

5/2t-t-(+3/2t)=0


Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R



Domain of the equation: 2t)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

-1t+5/2t-(+3/2t)=0

We get rid of parentheses

-1t+5/2t-3/2t=0

We multiply all the terms by the denominator


-1t*2t+5-3=0

We add all the numbers together, and all the variables

-1t*2t+2=0

Wy multiply elements

-2t^2+2=0

a = -2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-2)·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-2}=\frac{-4}{-4}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-2}=\frac{4}{-4}
=-1
$