5/2t-t=3(1/2t+3)

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Solution for 5/2t-t=3(1/2t+3) equation: 



5/2t-t=3(1/2t+3)

We move all terms to the left:

5/2t-t-(3(1/2t+3))=0



Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R





Domain of the equation: 2t+3))!=0

t∈R



We add all the numbers together, and all the variables

-1t+5/2t-(3(1/2t+3))=0

We calculate fractions


-1t+10t/4t^2+(-(3(1*2t)/4t^2=0

We add all the numbers together, and all the variables

-1t+10t/4t^2+(-(3(+1*2t)/4t^2=0

We multiply all the terms by the denominator


-1t*4t^2+10t+(-(3(+1*2t)=0



We calculate terms in parentheses: +(-(3(+1*2t), so:

-(3(+1*2t



We add all the numbers together, and all the variables

10t-1t*4t^2+(-(3(+1*2t)=0

Wy multiply elements

-4t^3+10t+(-(3(+1*2t)=0



We calculate terms in parentheses: +(-(3(+1*2t), so:

-(3(+1*2t



We do not support etpression: t^3

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