5/2w+8/w=1

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Solution for 5/2w+8/w=1 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

(5/2)*w+8/w = 1 // - 1

(5/2)*w+8/w-1 = 0

5/2*w^1+8*w^-1-1*w^0 = 0

(5/2*w^2-1*w^1+8*w^0)/(w^1) = 0 // * w^2

w^1*(5/2*w^2-1*w^1+8*w^0) = 0

w^1

(5/2)*w^2-w+8 = 0

(5/2)*w^2-w+8 = 0

DELTA = (-1)^2-(4*8*(5/2))

DELTA = -79

DELTA < 0

w in { } 

w belongs to the empty set

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