5/2w-12+4=-3/w-6

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Solution for 5/2w-12+4=-3/w-6 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

(5/2)*w-12+4 = -3/w-6 // + -3/w-6

(5/2)*w-(-3/w)-12+4+6 = 0

(5/2)*w+3*w^-1-12+4+6 = 0

5/2*w^1+3*w^-1-2*w^0 = 0

(5/2*w^2-2*w^1+3*w^0)/(w^1) = 0 // * w^2

w^1*(5/2*w^2-2*w^1+3*w^0) = 0

w^1

(5/2)*w^2-2*w+3 = 0

(5/2)*w^2-2*w+3 = 0

DELTA = (-2)^2-(3*4*(5/2))

DELTA = -26

DELTA < 0

w in { } 

w belongs to the empty set

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