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5/2x+1/4x+1=12
We move all terms to the left:
5/2x+1/4x+1-(12)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
5/2x+1/4x-11=0
We calculate fractions
20x/8x^2+2x/8x^2-11=0
We multiply all the terms by the denominator
20x+2x-11*8x^2=0
We add all the numbers together, and all the variables
22x-11*8x^2=0
Wy multiply elements
-88x^2+22x=0
a = -88; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-88)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-88}=\frac{-44}{-176} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-88}=\frac{0}{-176} =0 $
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