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5/2x+1=5/6x-4
We move all terms to the left:
5/2x+1-(5/6x-4)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x-4)!=0We get rid of parentheses
x∈R
5/2x-5/6x+4+1=0
We calculate fractions
30x/12x^2+(-10x)/12x^2+4+1=0
We add all the numbers together, and all the variables
30x/12x^2+(-10x)/12x^2+5=0
We multiply all the terms by the denominator
30x+(-10x)+5*12x^2=0
Wy multiply elements
60x^2+30x+(-10x)=0
We get rid of parentheses
60x^2+30x-10x=0
We add all the numbers together, and all the variables
60x^2+20x=0
a = 60; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·60·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*60}=\frac{-40}{120} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*60}=\frac{0}{120} =0 $
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