5/2x+2/9y=-527/18;3/5x+1/6y=-119/15

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Solution for 5/2x+2/9y=-527/18;3/5x+1/6y=-119/15 system of equations: 


  • /| (5/2)*x+(2/9)*y-(-527/18) = 0| (3/5)*x+(1/6)*y-(-119/15) = 0
  • We try to solve the equation: (5/2)*x+(2/9)*y-(-527/18) = 0
  • 5/2*x+2/9*y+527/18 = 0 // - 5/2*x+527/18
  • 2/9*y = -(5/2*x+527/18) // : 2/9
  • y = (-(5/2*x+527/18))/2/9
  • y = -9/2*(5/2*x+527/18)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (3/5)*x-9/2*(1/6)*(5/2*x+527/18)-(-119/15) = 0| y = -9/2*(5/2*x+527/18)
  • (3*x)/5-3/4*(5/2*x+527/18)+119/15 = 0
  • 119/15-51/40*x-527/24 = 0
  • -51/40*x-561/40 = 0
  • -51/40*x-561/40 = 0 // + 561/40
  • -51/40*x = 561/40 // : -51/40
  • x = 561/40/(-51/40)
  • x = -11
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -9/2*(5/2*x+527/18): 
  • y = -9/2*(527/18-11*5/2)
  • y = -9/2*(527/18-55/2)
  • y = -9/2*16/9
  • y = -8
  • We get a system of equations:
  • /| y = -8| x = -11

 

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