5/2x+3+1/x-6=0

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Solution for 5/2x+3+1/x-6=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/2)*x+1/x-6+3 = 0

5/2*x^1+1*x^-1-3*x^0 = 0

(5/2*x^2-3*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2-3*x^1+1*x^0) = 0

x^1

(5/2)*x^2-3*x+1 = 0

(5/2)*x^2-3*x+1 = 0

DELTA = (-3)^2-(1*4*(5/2))

DELTA = -1

DELTA < 0

x in { } 

x belongs to the empty set

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