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5/2x+5=1x
We move all terms to the left:
5/2x+5-(1x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x+5/2x+5=0
We multiply all the terms by the denominator
-1x*2x+5*2x+5=0
Wy multiply elements
-2x^2+10x+5=0
a = -2; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·(-2)·5
Δ = 140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{140}=\sqrt{4*35}=\sqrt{4}*\sqrt{35}=2\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{35}}{2*-2}=\frac{-10-2\sqrt{35}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{35}}{2*-2}=\frac{-10+2\sqrt{35}}{-4} $
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