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5/2x+6=5x-9
We move all terms to the left:
5/2x+6-(5x-9)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-5x+9+6=0
We multiply all the terms by the denominator
-5x*2x+9*2x+6*2x+5=0
Wy multiply elements
-10x^2+18x+12x+5=0
We add all the numbers together, and all the variables
-10x^2+30x+5=0
a = -10; b = 30; c = +5;
Δ = b2-4ac
Δ = 302-4·(-10)·5
Δ = 1100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1100}=\sqrt{100*11}=\sqrt{100}*\sqrt{11}=10\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{11}}{2*-10}=\frac{-30-10\sqrt{11}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{11}}{2*-10}=\frac{-30+10\sqrt{11}}{-20} $
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