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5/2x+6=x-16
We move all terms to the left:
5/2x+6-(x-16)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-x+16+6=0
We multiply all the terms by the denominator
-x*2x+16*2x+6*2x+5=0
Wy multiply elements
-2x^2+32x+12x+5=0
We add all the numbers together, and all the variables
-2x^2+44x+5=0
a = -2; b = 44; c = +5;
Δ = b2-4ac
Δ = 442-4·(-2)·5
Δ = 1976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1976}=\sqrt{4*494}=\sqrt{4}*\sqrt{494}=2\sqrt{494}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-2\sqrt{494}}{2*-2}=\frac{-44-2\sqrt{494}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+2\sqrt{494}}{2*-2}=\frac{-44+2\sqrt{494}}{-4} $
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