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5/2x+x=105
We move all terms to the left:
5/2x+x-(105)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+5/2x-105=0
We multiply all the terms by the denominator
x*2x-105*2x+5=0
Wy multiply elements
2x^2-210x+5=0
a = 2; b = -210; c = +5;
Δ = b2-4ac
Δ = -2102-4·2·5
Δ = 44060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44060}=\sqrt{4*11015}=\sqrt{4}*\sqrt{11015}=2\sqrt{11015}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-2\sqrt{11015}}{2*2}=\frac{210-2\sqrt{11015}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+2\sqrt{11015}}{2*2}=\frac{210+2\sqrt{11015}}{4} $
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