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5/2x-1/3x=17/18
We move all terms to the left:
5/2x-1/3x-(17/18)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
5/2x-1/3x-(+17/18)=0
We get rid of parentheses
5/2x-1/3x-17/18=0
We calculate fractions
(-306x^2)/108x^2+270x/108x^2+(-36x)/108x^2=0
We multiply all the terms by the denominator
(-306x^2)+270x+(-36x)=0
We get rid of parentheses
-306x^2+270x-36x=0
We add all the numbers together, and all the variables
-306x^2+234x=0
a = -306; b = 234; c = 0;
Δ = b2-4ac
Δ = 2342-4·(-306)·0
Δ = 54756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{54756}=234$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(234)-234}{2*-306}=\frac{-468}{-612} =13/17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(234)+234}{2*-306}=\frac{0}{-612} =0 $
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