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5/2x-13+4=x
We move all terms to the left:
5/2x-13+4-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x+5/2x-9=0
We multiply all the terms by the denominator
-1x*2x-9*2x+5=0
Wy multiply elements
-2x^2-18x+5=0
a = -2; b = -18; c = +5;
Δ = b2-4ac
Δ = -182-4·(-2)·5
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{91}}{2*-2}=\frac{18-2\sqrt{91}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{91}}{2*-2}=\frac{18+2\sqrt{91}}{-4} $
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