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5/2x-1=12x
We move all terms to the left:
5/2x-1-(12x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-12x+5/2x-1=0
We multiply all the terms by the denominator
-12x*2x-1*2x+5=0
Wy multiply elements
-24x^2-2x+5=0
a = -24; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·(-24)·5
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*-24}=\frac{-20}{-48} =5/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*-24}=\frac{24}{-48} =-1/2 $
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