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5/2x-2/8x=9
We move all terms to the left:
5/2x-2/8x-(9)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x!=0We calculate fractions
x!=0/8
x!=0
x∈R
40x/16x^2+(-4x)/16x^2-9=0
We multiply all the terms by the denominator
40x+(-4x)-9*16x^2=0
Wy multiply elements
-144x^2+40x+(-4x)=0
We get rid of parentheses
-144x^2+40x-4x=0
We add all the numbers together, and all the variables
-144x^2+36x=0
a = -144; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-144)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-144}=\frac{-72}{-288} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-144}=\frac{0}{-288} =0 $
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