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5/2x-3=3/x+2
We move all terms to the left:
5/2x-3-(3/x+2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
5/2x-3/x-2-3=0
We calculate fractions
5x/2x^2+(-6x)/2x^2-2-3=0
We add all the numbers together, and all the variables
5x/2x^2+(-6x)/2x^2-5=0
We multiply all the terms by the denominator
5x+(-6x)-5*2x^2=0
Wy multiply elements
-10x^2+5x+(-6x)=0
We get rid of parentheses
-10x^2+5x-6x=0
We add all the numbers together, and all the variables
-10x^2-1x=0
a = -10; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-10)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-10}=\frac{2}{-20} =-1/10 $
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