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5/2x-3=3x-1
We move all terms to the left:
5/2x-3-(3x-1)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-3x+1-3=0
We multiply all the terms by the denominator
-3x*2x+1*2x-3*2x+5=0
Wy multiply elements
-6x^2+2x-6x+5=0
We add all the numbers together, and all the variables
-6x^2-4x+5=0
a = -6; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·(-6)·5
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{34}}{2*-6}=\frac{4-2\sqrt{34}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{34}}{2*-6}=\frac{4+2\sqrt{34}}{-12} $
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