5/2x-4/x=3

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Solution for 5/2x-4/x=3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/2)*x-(4/x) = 3 // - 3

(5/2)*x-(4/x)-3 = 0

(5/2)*x-4*x^-1-3 = 0

5/2*x^1-4*x^-1-3*x^0 = 0

(5/2*x^2-3*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2-3*x^1-4*x^0) = 0

x^1

(5/2)*x^2-3*x-4 = 0

(5/2)*x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*4*(5/2))

DELTA = 49

DELTA > 0

x = (49^(1/2)+3)/(2*(5/2)) or x = (3-49^(1/2))/(2*(5/2))

x = 2 or x = -4/5

x in { -4/5, 2} 

x in { -4/5, 2 }

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